What is the domain of 1/(sqrt(x^4-37x^2+36)) ?

The domain of 1/(sqrt(x^4-37x^2+36)) is x 6

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domain of 1/(sqrt(x^4-37x^2+36))

domain

\frac{1}{x ^{4} - 37 x ^{2} + 36}

x < - 6 or - 1 < x < 1 or x > 6

Interval Notation

(- \infty, - 6) \cup (- 1, 1) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or - 1 \leq x \leq 1 or x \geq 6

Find undefined (singularity) points:

x = 6, x = - 6, x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 6 or - 1 < x < 1 or x > 6

(50, 4), (2, - 4)

f (x) = - \frac{5}{8} x + 10

f (x) = 3 x - 4

f (x) = 1 + 2 + 4 x

x - 1 + 3

What is the domain of 1/(sqrt(x^4-37x^2+36)) ?
The domain of 1/(sqrt(x^4-37x^2+36)) is x<-6\lor-1<x<1\lor x>6