What is the inverse of f(x)=x^2+3x+5 ?

The inverse of f(x)=x^2+3x+5 is (-3+sqrt(4x-11))/2 ,(-3-sqrt(4x-11))/2

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inverse of f(x)=x^2+3x+5

inverse

f (x) = x^{2} + 3 x + 5

\frac{- 3 + 4 x - 11}{2}, \frac{- 3 - 4 x - 11}{2}

Solution steps

y = x^{2} + 3 x + 5

Replace

x

with

y

x = y^{2} + 3 y + 5

Solve for

y, x = y^{2} + 3 y + 5

\frac{- 3 + 4 x - 11}{2}, \frac{- 3 - 4 x - 11}{2}

x - 3 y = 15

x = y^{2} + 3

\frac{x ^{2}}{2} + 1

f (x) = \frac{x ^{3} + 7 x ^{2} - x}{x ^{2} + 1}

\frac{x ^{\frac{3}{4}}}{x}

What is the inverse of f(x)=x^2+3x+5 ?
The inverse of f(x)=x^2+3x+5 is (-3+sqrt(4x-11))/2 ,(-3-sqrt(4x-11))/2