What is the inverse of f(x)=(x-3)^2+4 ?

The inverse of f(x)=(x-3)^2+4 is sqrt(x-4)+3,-sqrt(x-4)+3

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inverse of f(x)=(x-3)^2+4

inverse

f (x) = (x - 3)^{2} + 4

x - 4 + 3, - x - 4 + 3

Solution steps

y = (x - 3)^{2} + 4

Replace

x

with

y

x = (y - 3)^{2} + 4

Solve for

y, x = (y - 3)^{2} + 4

x - 4 + 3, - x - 4 + 3

y = \frac{1}{x} - 4

4 x - 7

f (x) = 0.09 x^{2} + 16 x + 350

12 x^{3}

x - 1

What is the inverse of f(x)=(x-3)^2+4 ?
The inverse of f(x)=(x-3)^2+4 is sqrt(x-4)+3,-sqrt(x-4)+3