What is the critical f(x)=2xe^{-x^2} ?

The critical f(x)=2xe^{-x^2} is x=-1/(sqrt(2)),x= 1/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=2xe^{-x^2}

critical points

f (x) = 2 x e^{- x^{2}}

x = - \frac{1}{2}, x = \frac{1}{2}

Solution steps

2 x e^{- x^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

2 x e^{- x^{2}} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}, x = \frac{1}{2}

f (x) = 1 0^{1 - x^{3}}

f (x) = \frac{( x - 6 )}{8}

f (x) = e^{- 0.5 x^{2}}

f (x) = \frac{5}{x + 4}

f (x) = 6 sec (x)

What is the critical f(x)=2xe^{-x^2} ?
The critical f(x)=2xe^{-x^2} is x=-1/(sqrt(2)),x= 1/(sqrt(2))