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Popular >

extreme f(x)=sqrt(4x^2+7)

Solution

extreme points

f (x) = 4 x^{2} + 7

Solution

Minimum (0, 7)

Solution steps

f^{'} (x) = \frac{4 x}{4 x ^{2} + 7}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

4 x^{2} + 7 : 7

Minimum (0, 7)

Popular Examples

midpoint (3,3),(-18,-5)midpoint

(3, 3), (- 18, - 5)

slope of x+y=4 slope

x + y = 4

domain of (4x-3)/(6-2x)domain

\frac{4 x - 3}{6 - 2 x}

domain of f(x)=(x-4)/(5-x)domain

f (x) = \frac{x - 4}{5 - x}

domain of f(x)=sqrt(-x)domain

f (x) = - x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(4x^2+7) ?
The extreme f(x)=sqrt(4x^2+7) is Minimum(0,sqrt(7))