What is the critical 8x^3-2x ?

The critical 8x^3-2x is x=-1/(2sqrt(3)),x= 1/(2sqrt(3))

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critical 8x^3-2x

critical points

8 x^{3} - 2 x

x = - \frac{1}{2 3}, x = \frac{1}{2 3}

Solution steps

8 x^{3} - 2 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2 3}, x = \frac{1}{2 3}

Identify critical points not in

f (x)

domain

Domain of

8 x^{3} - 2 x : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2 3}, x = \frac{1}{2 3}

f (x) = (x - 4)^{5}

f (x) = \frac{1}{10} x - \frac{1}{4}

\frac{2 x - 2}{x + 2}

g (x) = x^{2}

f (x) = \frac{x + 5}{2 - x}

What is the critical 8x^3-2x ?
The critical 8x^3-2x is x=-1/(2sqrt(3)),x= 1/(2sqrt(3))