What is the domain of (sqrt(x+3))/(x-9) ?

The domain of (sqrt(x+3))/(x-9) is -3 9

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domain of (sqrt(x+3))/(x-9)

domain

\frac{x + 3}{x - 9}

- 3 \leq x < 9 or x > 9

Interval Notation

[- 3, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 3 \leq x < 9 or x > 9

f (x) = \frac{1}{x} + 2

y = \frac{x}{x ^{2} - 4}

\frac{x ^{2}}{x ^{2} - 9}

f (x) = 4 x - 16

x^{2} - 8 x

What is the domain of (sqrt(x+3))/(x-9) ?
The domain of (sqrt(x+3))/(x-9) is -3<= x<9\lor x>9