What is the inverse of y=(49)/(x^2) ?

The inverse of y=(49)/(x^2) is (7sqrt(x))/x ,-(7sqrt(x))/x

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inverse of y=(49)/(x^2)

inverse

y = \frac{49}{x ^{2}}

\frac{7 x}{x}, - \frac{7 x}{x}

Solution steps

y = \frac{49}{x ^{2}}

Replace

x

with

y

x = \frac{49}{y ^{2}}

Solve for

y, x = \frac{49}{y ^{2}}

\frac{7 x}{x}, - \frac{7 x}{x}

x^{2} - 2 x - 15

4 x - 5 y + 15

4 x + 5 y = 15

f (x) = \frac{( 5 x - 2 )}{( 3 x + 6 )}

f (x) = \frac{3 x ^{3} - 3}{x - x ^{2}}

What is the inverse of y=(49)/(x^2) ?
The inverse of y=(49)/(x^2) is (7sqrt(x))/x ,-(7sqrt(x))/x