What is the perpendicular 3x+3y=72 ?

The perpendicular 3x+3y=72 is y=x+b

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perpendicular 3x+3y=72

perpendicular

3 x + 3 y = 72

y = x + b

Solution steps

Find the slope of

3 x + 3 y = 72 : m = - 1

Compute the slope of the perpendicular line:

m_{p} = 1

Line with slope m=

1 : y = x + b

y = x + b

y = - 1 + 3 x

2 tan (\frac{π x}{2})

(- 1, 6), (7, 16)

y = 1 0^{x}

x^{2} + 6 x + 2