What is the domain of f(x)= 1/(x^3-x^2-6x) ?

The domain of f(x)= 1/(x^3-x^2-6x) is x 3

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domain of f(x)= 1/(x^3-x^2-6x)

domain

f (x) = \frac{1}{x ^{3} - x ^{2} - 6 x}

x < - 2 or - 2 < x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2, x = 3

The function domain

x < - 2 or - 2 < x < 0 or 0 < x < 3 or x > 3

x^{2} + 3 x - 4

f (x) = \frac{x}{2}

7 x + 5 y = 4

\frac{1}{2} x^{2} - 5 x + 6

f (x) = 2 (\frac{1}{2})^{x}

What is the domain of f(x)= 1/(x^3-x^2-6x) ?
The domain of f(x)= 1/(x^3-x^2-6x) is x<-2\lor-2<x<0\lor 0<x<3\lor x>3