What is the inverse of f(x)=h(x)= 1/2 log_{3}(x) ?

The inverse of f(x)=h(x)= 1/2 log_{3}(x) is 9^x

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inverse of f(x)=h(x)= 1/2 log_{3}(x)

inverse

f (x) = h (x) = \frac{1}{2} lo g_{3} (x)

9^{x}

Solution steps

y = \frac{1}{2} lo g_{3} (x)

Replace

x

with

y

x = \frac{1}{2} lo g_{3} (y)

Solve for

y, x = \frac{1}{2} lo g_{3} (y)

9^{x}

\frac{2 x + 3}{x - 1}

f (x) = 2^{x - 3}

(4, 1), (0, 0)

(3, 2), (4, - 6)

- 2 (x - 2)^{2} + 4

What is the inverse of f(x)=h(x)= 1/2 log_{3}(x) ?
The inverse of f(x)=h(x)= 1/2 log_{3}(x) is 9^x