What is the critical 1/4 x^4-1/3 x^3-3x^2 ?

The critical 1/4 x^4-1/3 x^3-3x^2 is x=-2,x=0,x=3

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critical 1/4 x^4-1/3 x^3-3x^2

critical points

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - 3 x^{2}

x = - 2, x = 0, x = 3

Solution steps

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - 3 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - 3 x^{2} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 3

\frac{2 x}{x ^{2} - 1}

\frac{1}{1 - x + 1}

f (x) = 2 - 4 x

f (x) = \frac{x}{4}

y = 1

What is the critical 1/4 x^4-1/3 x^3-3x^2 ?
The critical 1/4 x^4-1/3 x^3-3x^2 is x=-2,x=0,x=3