What is the inverse of f(x)=x^2+6,x>= 0 ?

The inverse of f(x)=x^2+6,x>= 0 is sqrt(x-6),-sqrt(x-6)

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inverse of f(x)=x^2+6,x>= 0

inverse

f (x) = x^{2} + 6, x \geq 0

x - 6, - x - 6

Solution steps

y = x^{2} + 6

Replace

x

with

y

x = y^{2} + 6

Solve for

y, x = y^{2} + 6

x - 6, - x - 6

f (x) = 9^{3 x - 4} - 5

x - 5 = 4

f (x) = \frac{1}{( x + 4 ) ^{2}}

f (x) = \frac{5}{3} x^{3} - \frac{15}{2} x^{2}

What is the inverse of f(x)=x^2+6,x>= 0 ?
The inverse of f(x)=x^2+6,x>= 0 is sqrt(x-6),-sqrt(x-6)