What is the inverse of ((x+2)^2)/(x-1) ?

The inverse of ((x+2)^2)/(x-1) is (-4+x+sqrt(x^2-12x))/2 ,(-4+x-sqrt(x^2-12x))/2

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inverse of ((x+2)^2)/(x-1)

inverse

\frac{( x + 2 ) ^{2}}{x - 1}

\frac{- 4 + x + x ^{2} - 12 x}{2}, \frac{- 4 + x - x ^{2} - 12 x}{2}

Solution steps

y = \frac{( x + 2 ) ^{2}}{x - 1}

Replace

x

with

y

x = \frac{( y + 2 ) ^{2}}{y - 1}

Solve for

y, x = \frac{( y + 2 ) ^{2}}{y - 1}

\frac{- 4 + x + x ^{2} - 12 x}{2}, \frac{- 4 + x - x ^{2} - 12 x}{2}

f (x) = 2 x + 3 y - 5 = 0

f (x) = \frac{3 x}{x - 3}

f (x) = x^{2} - 3

f (x) = 8 + x

f (x) = - 2 - x

What is the inverse of ((x+2)^2)/(x-1) ?
The inverse of ((x+2)^2)/(x-1) is (-4+x+sqrt(x^2-12x))/2 ,(-4+x-sqrt(x^2-12x))/2