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Popular >

extreme f(x)=x^2+7x+6

Solution

extreme points

f (x) = x^{2} + 7 x + 6

Solution

Minimum (- \frac{7}{2}, - \frac{25}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x + 6 : - \frac{25}{4}

Minimum (- \frac{7}{2}, - \frac{25}{4})

Popular Examples

extreme f(x)=2x^3-3x^2-12x+6 extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 6

critical f(x)= x/(x^2+16)critical points

f (x) = \frac{x}{x ^{2} + 16}

domain of f(x)=sqrt((2+x)/(2-x))domain

f (x) = \frac{2 + x}{2 - x}

global 7x^2-9x-5 global extreme points

7 x^{2} - 9 x - 5

domain of sin(2/x)domain

sin (\frac{2}{x})

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x+6 ?
The extreme f(x)=x^2+7x+6 is Minimum(-7/2 ,-25/4)