What is the perpendicular y=-5x+3,(-8,-6) ?

The perpendicular y=-5x+3,(-8,-6) is y= 1/5 x-22/5

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perpendicular y=-5x+3,(-8,-6)

perpendicular

y = - 5 x + 3, (- 8, - 6)

y = \frac{1}{5} x - \frac{22}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 5 x + 3

that passes through

(- 8, - 6)

Find the slope of

y = - 5 x + 3 : m = - 5

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{5}

Find the line with slope m=

\frac{1}{5}

and passing through

(- 8, - 6) : y = \frac{1}{5} x - \frac{22}{5}

y = \frac{1}{5} x - \frac{22}{5}

f (x) = (x + 7)^{2} - 11

(3 - t)^{\frac{1}{6}}

2 x^{2}

e^{t a n (5 x)} sec^{2} (5 x) d x

- x^{4} + x^{3} + 9 x

What is the perpendicular y=-5x+3,(-8,-6) ?
The perpendicular y=-5x+3,(-8,-6) is y= 1/5 x-22/5