What is the critical f(x)=x^4-2x^2+6 ?

The critical f(x)=x^4-2x^2+6 is x=-1,x=0,x=1

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critical f(x)=x^4-2x^2+6

critical points

f (x) = x^{4} - 2 x^{2} + 6

x = - 1, x = 0, x = 1

Solution steps

x^{4} - 2 x^{2} + 6

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 2 x^{2} + 6 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

f (x) = lo g_{7} (x) - 7

- 4 x

f (x) = \frac{( x ^{2} )}{x - 3}

f (x) = x^{2} - 10 x + 8

f (x) = 20 - x

What is the critical f(x)=x^4-2x^2+6 ?
The critical f(x)=x^4-2x^2+6 is x=-1,x=0,x=1