What is the range of f(x)= x/(sqrt(2x)) ?

The range of f(x)= x/(sqrt(2x)) is f(x)>0

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range of f(x)= x/(sqrt(2x))

range

f (x) = \frac{x}{2 x}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x}{2 x} : x > 0

Simplify

\frac{x}{2 x} : \frac{x}{2}

Extreme Points of

\frac{x}{2} :

Minimum

(0, 0)

Find the range for the interval

0 < x < \infty : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

y = \frac{1}{2} x - 4, (9, - 6)

f (x) = \frac{4 x ^{2}}{x + 4}

4 y - 16 x = 8

f (x) = \frac{1}{x - 6}

f (x) = \frac{3}{x ( x - 4 )}

What is the range of f(x)= x/(sqrt(2x)) ?
The range of f(x)= x/(sqrt(2x)) is f(x)>0