What is the domain of sqrt(x^2-6) ?

The domain of sqrt(x^2-6) is x = sqrt(6)

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domain of sqrt(x^2-6)

domain

x^{2} - 6

x \leq - 6 or x \geq 6

Interval Notation

(- \infty, - 6] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 6

The function domain

x \leq - 6 or x \geq 6

F (x) = (x + 4) (x - 1)^{2}

f (x) = \frac{2 x}{3 x ^{2} - 12}

5^{x} + 3

f (x) = 3 x - 7

\frac{2 x + 1}{4 - x}

What is the domain of sqrt(x^2-6) ?
The domain of sqrt(x^2-6) is x<=-sqrt(6)\lor x>= sqrt(6)