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Popular >

distance (1,3),(4,7)

Solution

distance

(1, 3), (4, 7)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, 3)

and

(4, 7)

is

= (4 - 1)^{2} + (7 - 3)^{2}

Simplify

= 5

Popular Examples

inverse of 4x-1 inverse

4 x - 1

line (25000,11),(28000,9)line

(25000, 11), (28000, 9)

domain of y=2x domain

y = 2 x

domain of f(x)=((x^2-4)(x-3))/(x^2-x-6)domain

f (x) = \frac{( x ^{2} - 4 ) ( x - 3 )}{x ^{2} - x - 6}

parallel y=2x+3(3.1)parallel

y = 2 x + 3 (3.1)

Frequently Asked Questions (FAQ)

What is the distance (1,3),(4,7) ?
The distance (1,3),(4,7) is 5