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Popular >

range of f(x)=(x+1)^2

Solution

range

f (x) = (x + 1)^{2}

Solution

f (x) \geq 0

+1

Interval Notation

[0, \infty)

Solution steps

Vertex of

(x + 1)^{2} :

Minimum

(- 1, 0)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, 0)

f (x) \geq 0

Popular Examples

distance (0,-3),(6,3)distance

(0, - 3), (6, 3)

domain of f(x)=ln(x-x^2)domain

f (x) = ln (x - x^{2})

slope ofintercept-2x+3y=-4,(1,3)slope intercept

- 2 x + 3 y = - 4, (1, 3)

domain of f(x)=4.71238898 domain

f (x) = 4.71238898

domain of-0.5(x+3)^2+4 domain

- 0.5 (x + 3)^{2} + 4

Frequently Asked Questions (FAQ)

What is the range of f(x)=(x+1)^2 ?
The range of f(x)=(x+1)^2 is f(x)>= 0