What is the domain of f(x)=((x+4))/((x^2-9)) ?

The domain of f(x)=((x+4))/((x^2-9)) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((x+4))/((x^2-9))

domain

f (x) = \frac{( x + 4 )}{( x ^{2} - 9 )}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

(1, 2), (- 3, 5)

\frac{x}{x + 9}

f (x) = \frac{x + 3}{x - 8}

f (x) = x - 9

f (x) = 7 x + 11

What is the domain of f(x)=((x+4))/((x^2-9)) ?
The domain of f(x)=((x+4))/((x^2-9)) is x<-3\lor-3<x<3\lor x>3