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Popular >

extreme f(x)=(x^2-1)^{1/5}

Solution

extreme points

f (x) = (x^{2} - 1)^{\frac{1}{5}}

Solution

Minimum (0, - 1)

Solution steps

f^{'} (x) = \frac{2 x}{5 ( x ^{2} - 1 ) ^{\frac{4}{5}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

(x^{2} - 1)^{\frac{1}{5}} : - 1

Minimum (0, - 1)

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perpendicular y= 1/2 x-1 perpendicular

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asymptotes of f(x)=csc(x)asymptotes

f (x) = csc (x)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2-1)^{1/5} ?
The extreme f(x)=(x^2-1)^{1/5} is Minimum(0,-1)