What is the slope of y=-0.000008x^2-0.0001x+0.0029 ?

The slope of y=-0.000008x^2-0.0001x+0.0029 is -0.000016x-0.0001

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slope of y=-0.000008x^2-0.0001x+0.0029

slope

y = - 0.000008 x^{2} - 0.0001 x + 0.0029

- 0.000016 x - 0.0001

Solution steps

y = - 0.000008 x^{2} - 0.0001 x + 0.0029

In order to find the slope of the function, take the derivative of

- 0.000008 x^{2} - 0.0001 x + 0.0029

\frac{d}{d x} (- 0.000008 x^{2} - 0.0001 x + 0.0029) = - 0.000016 x - 0.0001

- 0.000016 x - 0.0001

16 - x^{2} + x + 1

e^{- x} (x^{2} - 3)

\frac{7 x + 2}{x ^{2} + x - 2}

\frac{x ^{3} + 4}{2}

6 x - 5 (x + 2) = 5 y - x

What is the slope of y=-0.000008x^2-0.0001x+0.0029 ?
The slope of y=-0.000008x^2-0.0001x+0.0029 is -0.000016x-0.0001