What is the critical f(x)=ln(4x^2-2x) ?

The critical f(x)=ln(4x^2-2x) is None

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critical f(x)=ln(4x^2-2x)

critical points

f (x) = ln (4 x^{2} - 2 x)

None

Solution steps

ln (4 x^{2} - 2 x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{4}, x = 0, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

ln (4 x^{2} - 2 x) : x < 0 or x > \frac{1}{2}

ln (4 x^{2} - 2 x)

is not defined at

x = \frac{1}{4}, x = 0, x = \frac{1}{2}

, therefore:

None

f (x) = 13 - x

f (x) = \frac{x ^{2} - 9 x}{x ^{2} - 81}

y = csc (θ)

f (x) = 7 x - 1

(6.7) (4.3)