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Popular >

distance (-2,3),(2,2)

Solution

distance

(- 2, 3), (2, 2)

Solution

17

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 3)

and

(2, 2)

is

= (2 - (- 2))^{2} + (2 - 3)^{2}

Simplify

= 17

Popular Examples

domain of y=4-x^2 domain

y = 4 - x^{2}

inverse of-5sqrt(2x+8)inverse

- 5 2 x + 8

inflection y=-3/(x+1)inflection points

y = - \frac{3}{x + 1}

perpendicular y= 4/5 x+4,(8,-2)perpendicular

y = \frac{4}{5} x + 4, (8, - 2)

intercepts of f(x)= x/2-arctan(x)intercepts

f (x) = \frac{x}{2} - arctan (x)

Frequently Asked Questions (FAQ)

What is the distance (-2,3),(2,2) ?
The distance (-2,3),(2,2) is square root of 17