What is the domain of f(x)=e^{(x+1)/(x-1)}+1/x ?

The domain of f(x)=e^{(x+1)/(x-1)}+1/x is x 1

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domain of f(x)=e^{(x+1)/(x-1)}+1/x

domain

f (x) = e^{\frac{x + 1}{x - 1}} + \frac{1}{x}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = e^{x - 3}

y = lo g_{6} (x + 2)

f (x) = 2.5 x + 5.5

\frac{x}{4}

f (x) = \frac{x}{x ^{2} + 4}

What is the domain of f(x)=e^{(x+1)/(x-1)}+1/x ?
The domain of f(x)=e^{(x+1)/(x-1)}+1/x is x<0\lor 0<x<1\lor x>1