What is the domain of f(x)=(9x(x-7))/(2x^2-5x-3) ?

The domain of f(x)=(9x(x-7))/(2x^2-5x-3) is x 3

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domain of f(x)=(9x(x-7))/(2x^2-5x-3)

domain

f (x) = \frac{9 x ( x - 7 )}{2 x ^{2} - 5 x - 3}

x < - \frac{1}{2} or - \frac{1}{2} < x < 3 or x > 3

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < 3 or x > 3

f (x) = x^{3} - 3 x^{2} - 3 x + 5

f (x) = - \frac{3}{x - 1} - 2

f (x) = 3 - (x + 12.2)^{2} - 3

x^{3} + 8

sin (2 π x)

What is the domain of f(x)=(9x(x-7))/(2x^2-5x-3) ?
The domain of f(x)=(9x(x-7))/(2x^2-5x-3) is x<-1/2 \lor-1/2 <x<3\lor x>3