What is the domain of (6x)/(x^2-1) ?

The domain of (6x)/(x^2-1) is x 1

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domain of (6x)/(x^2-1)

domain

\frac{6 x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = e^{4 x - 7}

f (x) = 3 lo g_{5} (7 x - 4)

f (x) = x^{4} + 8 x^{3} + 16 x^{2}

f (x) = sin (7 x)

f (x) = \frac{- 2 - 7 x}{3 x - 1}

What is the domain of (6x)/(x^2-1) ?
The domain of (6x)/(x^2-1) is x<-1\lor-1<x<1\lor x>1