What is the extreme f(x)=-2x+6x^{2/3} ?

The extreme f(x)=-2x+6x^{2/3} is Minimum(0,0),Maximum(8,8)

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extreme f(x)=-2x+6x^{2/3}

extreme points

f (x) = - 2 x + 6 x^{\frac{2}{3}}

Minimum (0, 0), Maximum (8, 8)

Solution steps

f^{'} (x) = - 2 + \frac{4}{x ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < \frac{1}{8},

Increasing

: \frac{1}{8} < x < \infty

Plug

x = 0

into

- 2 x + 6 x^{\frac{2}{3}} : 0

Minimum (0, 0)

Plug

x = 8

into

- 2 x + 6 x^{\frac{2}{3}} : 8

Maximum (8, 8)

Minimum (0, 0), Maximum (8, 8)

f (x) = x^{4} - 4 x^{3} + 6

f (x) = x^{3} + 3 x + 5

y = 4 x^{2}

f (x) = \frac{5}{( \frac{5}{x} )}

f (x) = ln (5 x - 2)

What is the extreme f(x)=-2x+6x^{2/3} ?
The extreme f(x)=-2x+6x^{2/3} is Minimum(0,0),Maximum(8,8)