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Popular >

range of-x^2-8x+9

Solution

range

- x^{2} - 8 x + 9

Solution

f (x) \leq 25

+1

Interval Notation

(- \infty, 25]

Solution steps

Vertex of

- x^{2} - 8 x + 9 :

Maximum

(- 4, 25)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (- 4, 25)

f (x) \leq 25

Popular Examples

domain of f(x)=ln(((2-x))/x)domain

f (x) = ln (\frac{( 2 - x )}{x})

domain of ([sqrt(2-x)])/([sqrt(x^2-1)])domain

\frac{[ 2 - x ]}{[ x ^{2} - 1 ]}

domain of f(x)=(sqrt(x-8))/(x(x-9))domain

f (x) = \frac{x - 8}{x ( x - 9 )}

perpendicular 3y+6x=9 perpendicular

3 y + 6 x = 9

symmetry 1(x+4)^2-2 symmetry

1 (x + 4)^{2} - 2

Frequently Asked Questions (FAQ)

What is the range of-x^2-8x+9 ?
The range of-x^2-8x+9 is f(x)<= 25