What is the domain of ((x^2-9))/(x-3) ?

The domain of ((x^2-9))/(x-3) is x 3

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domain of ((x^2-9))/(x-3)

domain

\frac{( x ^{2} - 9 )}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = 3 [x - 2] - 4

f (x) = - \frac{1}{2 9 - x}

f (x) = \frac{2}{5} x + 4

f (x) = 3 x^{3} - 12

f (x) = - 3 - 2 x

What is the domain of ((x^2-9))/(x-3) ?
The domain of ((x^2-9))/(x-3) is x<3\lor x>3