What is the extreme f(x)= 1/3 x^3-3x ?

The extreme f(x)= 1/3 x^3-3x is Maximum(-sqrt(3),2sqrt(3)),Minimum(sqrt(3),-2sqrt(3))

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extreme f(x)= 1/3 x^3-3x

extreme points

f (x) = \frac{1}{3} x^{3} - 3 x

Maximum (- 3, 23), Minimum (3, - 23)

Solution steps

f^{'} (x) = x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

\frac{1}{3} x^{3} - 3 x : 23

Maximum (- 3, 23)

Plug

x = 3

into

\frac{1}{3} x^{3} - 3 x : - 23

Minimum (3, - 23)

Maximum (- 3, 23), Minimum (3, - 23)

f (x) = 5 x + 1

f (x) = 3 x^{2} - 1

f (x) = \frac{x + 2}{x ^{2}}

f (x) = \frac{x ^{2} - 4}{x - 3}

f (x) = \frac{x + 1}{x - 3}

What is the extreme f(x)= 1/3 x^3-3x ?
The extreme f(x)= 1/3 x^3-3x is Maximum(-sqrt(3),2sqrt(3)),Minimum(sqrt(3),-2sqrt(3))