What is the perpendicular y=-5x+3 ?

The perpendicular y=-5x+3 is y= 1/5 x+b

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perpendicular y=-5x+3

perpendicular

y = - 5 x + 3

y = \frac{1}{5} x + b

Solution steps

Find the slope of

y = - 5 x + 3 : m = - 5

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{5}

Line with slope m=

\frac{1}{5} : y = \frac{1}{5} x + b

y = \frac{1}{5} x + b

f (x) = \frac{2 x + 2}{x - 1}

f (x) = 9 cos (x) [0, 2 π]

x^{2} ln (x)

f (x) = \frac{2 x ^{2} - 5 x + 8}{x - 3}

f (x) = 1 + x^{4}