What is the inverse of f(x)=sqrt(x^2+8x) ?

The inverse of f(x)=sqrt(x^2+8x) is -4+sqrt(x^2+16),-sqrt(x^2+16)-4

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inverse of f(x)=sqrt(x^2+8x)

inverse

f (x) = x^{2} + 8 x

- 4 + x^{2} + 16, - x^{2} + 16 - 4

Solution steps

y = x^{2} + 8 x

Replace

x

with

y

x = y^{2} + 8 y

Solve for

y, x = y^{2} + 8 y

- 4 + x^{2} + 16, - x^{2} + 16 - 4

f (x) = 5 (x + 4)^{2} - 1

y = 7 - 4 x

f (x) = \frac{x ^{2} - 2 x - 3}{x + 1}

f (x) = 4 2 x - 3

f (x) = \frac{x ^{2}}{2} - x - \frac{9}{2}

What is the inverse of f(x)=sqrt(x^2+8x) ?
The inverse of f(x)=sqrt(x^2+8x) is -4+sqrt(x^2+16),-sqrt(x^2+16)-4