What is the distance (1/4 ,5),(7, 2/3) ?

The distance (1/4 ,5),(7, 2/3) is (sqrt(9265))/(12)

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distance (1/4 ,5),(7, 2/3)

distance

(\frac{1}{4}, 5), (7, \frac{2}{3})

\frac{9265}{12}

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(\frac{1}{4}, 5)

and

(7, \frac{2}{3})

= (7 - \frac{1}{4})^{2} + (\frac{2}{3} - 5)^{2}

Simplify

= \frac{9265}{12}

y = 74 x - 3, (5, - 4)

2 x - 3 y = - 2

f (x) = \frac{2}{x - 1} + 3

y = \frac{24}{6} x + 24

25 - x^{2} + x + 1

What is the distance (1/4 ,5),(7, 2/3) ?
The distance (1/4 ,5),(7, 2/3) is (sqrt(9265))/(12)