What is the domain of f(x)= 1/(x^2+8) ?

The domain of f(x)= 1/(x^2+8) is -infinity <x<infinity

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domain of f(x)= 1/(x^2+8)

domain

f (x) = \frac{1}{x ^{2} + 8}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 4 x^{2} - 24 x - 30

f (x) = - 3 y + 7 x = - 3

f (x) = \frac{- 5 x ^{2} + 6 x - 2}{x ^{2} + 3}

9 x + y = 0

f (x) = 5 x - 3 y = 15

What is the domain of f(x)= 1/(x^2+8) ?
The domain of f(x)= 1/(x^2+8) is -infinity <x<infinity