What is the domain of f(x)=\sqrt[3]{x}+1 ?

The domain of f(x)=\sqrt[3]{x}+1 is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x}+1

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = x^{3} - 4 x^{2} - 4 x + 16

f (x) = 3 x^{2} - 16 x + 5

f (x) = \frac{1}{( x + 1 ) ^{2}}

4 (\frac{2}{3})^{x} + 1

\frac{x ^{2} + 4 x + 6}{3 x ^{2} + 12 x + 12}

What is the domain of f(x)=\sqrt[3]{x}+1 ?
The domain of f(x)=\sqrt[3]{x}+1 is -infinity <x<infinity