What is the inverse of f(x)=9-4x^2 ?

The inverse of f(x)=9-4x^2 is sqrt(-(x-9)/4),-sqrt(-(x-9)/4)

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inverse of f(x)=9-4x^2

inverse

f (x) = 9 - 4 x^{2}

- \frac{x - 9}{4}, - - \frac{x - 9}{4}

Solution steps

y = 9 - 4 x^{2}

Replace

x

with

y

x = 9 - 4 y^{2}

Solve for

y, x = 9 - 4 y^{2}

- \frac{x - 9}{4}, - - \frac{x - 9}{4}

f (x) = 4 ln (x) + 8

f (x) = \frac{x + 1}{x ^{2} - 1}

\frac{- 4 - 5 x}{3 x - 1}

f (x) = \frac{1}{2} x^{2}

f (x) = 2 x - 1 + 3

What is the inverse of f(x)=9-4x^2 ?
The inverse of f(x)=9-4x^2 is sqrt(-(x-9)/4),-sqrt(-(x-9)/4)