What is the asymptotes of y=(x^2-3x-4)/(1-3x-4x^2) ?

The asymptotes of y=(x^2-3x-4)/(1-3x-4x^2) is Vertical: x= 1/4 ,Horizontal: y=-1/4

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asymptotes of y=(x^2-3x-4)/(1-3x-4x^2)

asymptotes

y = \frac{x ^{2} - 3 x - 4}{1 - 3 x - 4 x ^{2}}

Vertical : x = \frac{1}{4}, Horizontal : y = - \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x - 4}{1 - 3 x - 4 x ^{2}} : x = \frac{1}{4}

Horizontal Asymptotes of

\frac{x ^{2} - 3 x - 4}{1 - 3 x - 4 x ^{2}} : y = - \frac{1}{4}

Slant Asymptotes of

\frac{x ^{2} - 3 x - 4}{1 - 3 x - 4 x ^{2}} :

None

Vertical : x = \frac{1}{4}, Horizontal : y = - \frac{1}{4}

\frac{20}{10 + e ^{x}}

3 x + 2 y = 10

x^{2} - 121

\frac{x}{x ^{2} - 16}

f (x) = ∣ x - 2 ∣

What is the asymptotes of y=(x^2-3x-4)/(1-3x-4x^2) ?
The asymptotes of y=(x^2-3x-4)/(1-3x-4x^2) is Vertical: x= 1/4 ,Horizontal: y=-1/4