What is the asymptotes of f(x)=(x^2-2x)/(2x^2+2x) ?

The asymptotes of f(x)=(x^2-2x)/(2x^2+2x) is Vertical: x=-1,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2-2x)/(2x^2+2x)

asymptotes

f (x) = \frac{x ^{2} - 2 x}{2 x ^{2} + 2 x}

Vertical : x = - 1, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x}{2 x ^{2} + 2 x} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} - 2 x}{2 x ^{2} + 2 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 2 x}{2 x ^{2} + 2 x} :

None

Vertical : x = - 1, Horizontal : y = \frac{1}{2}

f (x) = 7 x^{3} + 3

\frac{x ^{4}}{x ^{2} + x - 6}

f (x) = 5 x

f (x) = \frac{( x - 2 ) ^{2}}{( x - 2 )}

- \frac{1}{2 4 - x}

What is the asymptotes of f(x)=(x^2-2x)/(2x^2+2x) ?
The asymptotes of f(x)=(x^2-2x)/(2x^2+2x) is Vertical: x=-1,Horizontal: y= 1/2