What is the inverse of f(x)=x^2-4x-5 ?

The inverse of f(x)=x^2-4x-5 is 2+sqrt(x+9),2-sqrt(x+9)

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inverse of f(x)=x^2-4x-5

inverse

f (x) = x^{2} - 4 x - 5

2 + x + 9, 2 - x + 9

Solution steps

y = x^{2} - 4 x - 5

Replace

x

with

y

x = y^{2} - 4 y - 5

Solve for

y, x = y^{2} - 4 y - 5

2 + x + 9, 2 - x + 9

f (x) = \frac{x ^{3}}{x + 2}

f (x) = \frac{8 x ^{2}}{x ^{4} + 16}

f (x) = (x - 2)^{2}

\frac{3 x}{x + 7 ( x - 2 )}

f (x) = \frac{3 - x ^{2}}{x ^{2} + 2 x - 15}

What is the inverse of f(x)=x^2-4x-5 ?
The inverse of f(x)=x^2-4x-5 is 2+sqrt(x+9),2-sqrt(x+9)