What is the asymptotes of f(x)=(2x^2-2x-1)/(5x^2) ?

The asymptotes of f(x)=(2x^2-2x-1)/(5x^2) is Vertical: x=0,Horizontal: y= 2/5

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asymptotes of f(x)=(2x^2-2x-1)/(5x^2)

asymptotes

f (x) = \frac{2 x ^{2} - 2 x - 1}{5 x ^{2}}

Vertical : x = 0, Horizontal : y = \frac{2}{5}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 2 x - 1}{5 x ^{2}} : x = 0

Horizontal Asymptotes of

\frac{2 x ^{2} - 2 x - 1}{5 x ^{2}} : y = \frac{2}{5}

Slant Asymptotes of

\frac{2 x ^{2} - 2 x - 1}{5 x ^{2}} :

None

Vertical : x = 0, Horizontal : y = \frac{2}{5}

f (x) = \frac{x ^{2} - 6 x + 8}{x - 3}

f (x) = ln (x + 8)

\frac{4 x - 2}{x - 1}

f (x) = \frac{x + 3}{2 x - 4}

f (x) = 14 - x^{2}

What is the asymptotes of f(x)=(2x^2-2x-1)/(5x^2) ?
The asymptotes of f(x)=(2x^2-2x-1)/(5x^2) is Vertical: x=0,Horizontal: y= 2/5