What is the inverse of f(t)=10e^{0.1t} ?

The inverse of f(t)=10e^{0.1t} is (ln(t/(10)))/(0.1)

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inverse of f(t)=10e^{0.1t}

inverse

f (t) = 10 e^{0.1 t}

\frac{ln ( \frac{t}{10} )}{0.1}

Solution steps

y = 10 e^{0.1 t}

Replace

t

with

y

t = 10 e^{0.1 y}

Solve for

y, t = 10 e^{0.1 y}

\frac{ln ( \frac{t}{10} )}{0.1}

f (x) = 3 cot (\frac{π}{7} x)

f (x) = \frac{x ^{2}}{1 - x}

f (x) = \frac{x ^{2} + 2 x - 15}{x ^{2} - 4}

x^{2} - x - 1

(- 2.1) - \frac{1}{2}

What is the inverse of f(t)=10e^{0.1t} ?
The inverse of f(t)=10e^{0.1t} is (ln(t/(10)))/(0.1)