What is the domain of g(x)= x/(x^2-9) ?

The domain of g(x)= x/(x^2-9) is x 3

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domain of g(x)= x/(x^2-9)

domain

g (x) = \frac{x}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = 7 + 8 x - x^{3}

f (x) = 9 - x + 5

- \frac{1}{3} (x - 11)^{2} + 27

\frac{x ^{2} - 1}{x - 1}

f (x) = \frac{x - 6}{x + 6}

What is the domain of g(x)= x/(x^2-9) ?
The domain of g(x)= x/(x^2-9) is x<-3\lor-3<x<3\lor x>3