What is the range of f(x)=2-x^2,-4<= x<= 4 ?

The range of f(x)=2-x^2,-4<= x<= 4 is -14<= f(x)<= 2

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range of f(x)=2-x^2,-4<= x<= 4

range

f (x) = 2 - x^{2}, - 4 \leq x \leq 4

- 14 \leq f (x) \leq 2

Interval Notation

[- 14, 2]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

2 - x^{2}, - 4 \leq x \leq 4 : - 4 \leq x \leq 4

Extreme Points of

2 - x^{2}, - 4 \leq x \leq 4 :

Minimum

(- 4, - 14),

Maximum

(0, 2),

Minimum

(4, - 14)

Find the range for the interval

- 4 \leq x \leq 4 : - 14 \leq f (x) \leq 2

Combine the ranges of all domain intervals to obtain the function range

- 14 \leq f (x) \leq 2

f (x) = - \frac{1}{4}

f (x) = \frac{8 x}{9 x - 1}

y = - \frac{x ^{3}}{x ^{2} - 4}

y = - 2 (x - 3)^{2} + 4

4 x - 2

What is the range of f(x)=2-x^2,-4<= x<= 4 ?
The range of f(x)=2-x^2,-4<= x<= 4 is -14<= f(x)<= 2