What is the domain of (x-3)/(x-7)+sqrt(x+8) ?

The domain of (x-3)/(x-7)+sqrt(x+8) is -8 7

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domain of (x-3)/(x-7)+sqrt(x+8)

domain

\frac{x - 3}{x - 7} + x + 8

- 8 \leq x < 7 or x > 7

Interval Notation

[- 8, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 8 \leq x < 7 or x > 7

f (x) = x - 1

x^{2} - 3 x - 10

f (x) = \frac{( x ^{2} + 1 )}{x ^{3} + 2}

12 - 4 x

f (x) = 2 x + 9 - 4

What is the domain of (x-3)/(x-7)+sqrt(x+8) ?
The domain of (x-3)/(x-7)+sqrt(x+8) is -8<= x<7\lor x>7