What is the domain of f(x)=\sqrt[5]{x/(7-x^2)} ?

The domain of f(x)=\sqrt[5]{x/(7-x^2)} is x sqrt(7)

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domain of f(x)=\sqrt[5]{x/(7-x^2)}

domain

x < - 7 or - 7 < x < 7 or x > 7

Interval Notation

(- \infty, - 7) \cup (- 7, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 7

The function domain

x < - 7 or - 7 < x < 7 or x > 7

f (x) = \frac{ln ^{2} ( x )}{x}

f (x) = cos (2 x)

f (x) = \frac{1}{x} + 9

(- 4, - 2), (3, 3)

f (x) = \frac{e ^{x}}{1 - x}

What is the domain of f(x)=\sqrt[5]{x/(7-x^2)} ?
The domain of f(x)=\sqrt[5]{x/(7-x^2)} is x<-sqrt(7)\lor-sqrt(7)<x<sqrt(7)\lor x>sqrt(7)