What is the inverse of (x^2-16)/(7x^2) ?

The inverse of (x^2-16)/(7x^2) is sqrt(-(16)/(7x-1)),-sqrt(-(16)/(7x-1))

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inverse of (x^2-16)/(7x^2)

inverse

\frac{x ^{2} - 16}{7 x ^{2}}

- \frac{16}{7 x - 1}, - - \frac{16}{7 x - 1}

Solution steps

y = \frac{x ^{2} - 16}{7 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 16}{7 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 16}{7 y ^{2}}

- \frac{16}{7 x - 1}, - - \frac{16}{7 x - 1}

\frac{x ^{2} - 1}{x ^{2} - 4}

f (x) = - 7 x - 6 y = - 15 - 7 x - 6 y = - 15

\frac{5}{4}

y = - \frac{1}{4} x + 5, (5, - 9)

f (x) = - 5 x + 5

What is the inverse of (x^2-16)/(7x^2) ?
The inverse of (x^2-16)/(7x^2) is sqrt(-(16)/(7x-1)),-sqrt(-(16)/(7x-1))