What is the asymptotes of f(x)=(2x^2+4x)/(x^3-8) ?

The asymptotes of f(x)=(2x^2+4x)/(x^3-8) is Vertical: x=2,Horizontal: y=0

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asymptotes of f(x)=(2x^2+4x)/(x^3-8)

asymptotes

f (x) = \frac{2 x ^{2} + 4 x}{x ^{3} - 8}

Vertical : x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 4 x}{x ^{3} - 8} : x = 2

Horizontal Asymptotes of

\frac{2 x ^{2} + 4 x}{x ^{3} - 8} : y = 0

Slant Asymptotes of

\frac{2 x ^{2} + 4 x}{x ^{3} - 8} :

None

Vertical : x = 2, Horizontal : y = 0

y = \frac{x ^{2} - 5 x - 6}{x - 6}

(4, - 9), (- 5, 3)

- 5 cos (6 x)

f (x) = \frac{4}{6 - 2 x}

What is the asymptotes of f(x)=(2x^2+4x)/(x^3-8) ?
The asymptotes of f(x)=(2x^2+4x)/(x^3-8) is Vertical: x=2,Horizontal: y=0